Question

rationalize the denominator of 6/√3-√5​

Answer 1

Answer:

$- 3( \sqrt{3} + \sqrt{5} )$

Step-by-step explanation:

$\frac{6}{ \sqrt{3 } - \sqrt{5} } \times \frac{ \sqrt{3 } + \sqrt{5} }{ \sqrt{3 } + \sqrt{5} }$

$\frac{6 (\sqrt{3 } + \sqrt{5} )}{3 - 5}$

$\frac{6 (\sqrt{3 } + \sqrt{5} )}{ - 2}$

$- 3 ( \sqrt{3} + \sqrt{5} )$

Answer 2

6(✓3+✓5) /(✓3-✓5)(✓3+√5)

=(6✓3+6✓5) /(✓3)^2-(✓5)^2{using identity (a+b)(a-b)}

=6✓3+6✓5/3-5

=6✓3+6✓5 /-2

=-6✓3-6✓5/2