Math, asked by sujashree21, 3 months ago

rationalize the denominator of √7 + 2 ÷ √7 - 2​

Answers

Answered by rehakhan25
1

Answer:

hope it can help you

Step-by-step explanation:

the conjugate pair of

 \sqrt{7}  \:  - 2

is

 \sqrt{7}  + 2

 \frac{ \sqrt{7} + 2 }{ \sqrt{7} - 2 }  =   \frac{ \sqrt{7} + 2 }{ \sqrt{7} - 2 } \:  \times \frac{ \sqrt{7} + 2 }{ \sqrt{7}  +  2 }

 \:  \:  \:  \:  \:  \:  \:  \:  \:    =  \frac{7 + 4}{7 - 4}

  \:  \:  \:  \:  \:  \:  \:  \:  \:  \:  = \frac{11}{3}

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