Rationalize the denominator of a)4/5√5 and B)4√3+5√2/√48+√18.
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a) 4/5√5
4× √5 /5√5 × √5
4√5 / 5×5
4√5/25
b) 4√3+5√2/√48+√18
4√3+5√2/√16×3+√9×2
(4√3+5√2) / (4√3+3√2)
(4√3+5√2) (4√3- 3√2)/ (4√3+3√2)(4√3 - 3√2)
(16×3 - 12√6 +20√6 - 15×2) / (4√3)² - (3√2)²
(48 +8√6 -30) / 48 - 18
(18 +8√6) / 30
(9+ 4√6) / 15
4× √5 /5√5 × √5
4√5 / 5×5
4√5/25
b) 4√3+5√2/√48+√18
4√3+5√2/√16×3+√9×2
(4√3+5√2) / (4√3+3√2)
(4√3+5√2) (4√3- 3√2)/ (4√3+3√2)(4√3 - 3√2)
(16×3 - 12√6 +20√6 - 15×2) / (4√3)² - (3√2)²
(48 +8√6 -30) / 48 - 18
(18 +8√6) / 30
(9+ 4√6) / 15
golu46:
my ans is same
Answered by
4
a) 4/5√5. multiple both denomination and numerator by √5
= 4×√5/5√5×√5
=4√5/5×5
=4√5/25
therefore denomination is rationalize
b)4√3+5√2/√48+√18
=4√3+5√2×√48/√48×√48+√18
=4√3+5×4√6/48+√18. LCM of 1and 48 is 48. now multiple numerator by 48
=4×48√3+20√6×48+√18×48
=192√3+960√6+144√3/48
=336√3+969√6/48
therefore denomination is rationalize
= 4×√5/5√5×√5
=4√5/5×5
=4√5/25
therefore denomination is rationalize
b)4√3+5√2/√48+√18
=4√3+5√2×√48/√48×√48+√18
=4√3+5×4√6/48+√18. LCM of 1and 48 is 48. now multiple numerator by 48
=4×48√3+20√6×48+√18×48
=192√3+960√6+144√3/48
=336√3+969√6/48
therefore denomination is rationalize
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