Math, asked by pravesh4576, 8 months ago

Rationalize the denominator of root 2/root 3 +root 2

Answers

Answered by Anonymous
3

\huge{\mathcal{\blue{\underline{Answer}}}}

  = \frac{ \sqrt{2} }{ \sqrt{3} +  \sqrt{2}  }  \\  =  \frac{ \sqrt{2} }{ \sqrt{3}  +  \sqrt{2} }  \times  \frac{ \sqrt{3}  -  \sqrt{2} }{ \sqrt{3  } -  \sqrt{2}  }  \\  =  \frac{ \sqrt{6} - 2}{( \sqrt{3}) {}^{2}  - ( \sqrt{2}  ) {}^{2} }  \\  =  \frac{ \sqrt{6}  - 2}{3 - 2}  \\  =  \sqrt{6}  - 2

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