Math, asked by ssanthisanthiya52, 10 hours ago

rationalize the denominator of root 5by root 6+root 2​

Answers

Answered by tanmaysakhuja0716
0

Step-by-step explanation:

√5. √5. √6-√2. √30-√2

------------- = ----------- × ----------------- = --------------

√6+√2. √6+√2. √6-√2. 6-2

= √30-√2

------------------

4

Answered by vijaykumar9984078984
0

Answer:

 \frac{ \sqrt{5} }{6 +  \sqrt{2} }  \times  \frac{6  -   \sqrt{2} }{6 -  \sqrt{2} }  \\  =   \frac{6 \sqrt{5}  -  \sqrt{10} }{ {6}^{2}  -  { \sqrt{2} }^{2} }  \\  =  \frac{6 \sqrt{5} -  \sqrt{10}  }{36 - 2}  \\  =  \frac{6 \sqrt{5}  -  \sqrt{10} }{34}

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