Question

rationalize the denominator of
$\frac{2 - \sqrt{3 } }{2 - \sqrt{3} }$
​

Answer 1

Answer:

1 is correct answer

Step-by-step explanation:

$\frac{2 - \sqrt{3} }{2 - \sqrt{3} } \times \frac{2 + \sqrt{3} }{2 + \sqrt{3} } \\ = \frac{ {2}^{2} - \sqrt{ {3}^{2} } }{ {2}^{2} - \sqrt{ {3}^{2} } } \\ = \frac{4 - 3}{4 - 3} \\ = \frac{1}{1} = 1$