Question

rationalize the denominator of the folllowing 1/(√6+√7) and 1/(√7-√5)​

Answer 1

Answer:

√6-√7/-1,,,,,√7+√5/2

Step-by-step explanation:

1. 1/√6+√7×√6-√7/√6-√7=√6-√7/-1
2. 1/√7-√5×√7+√5/√7+√5=√7+√5/2

Answer 2

1/root 6+ 1/root 7 =root 6 -root 7/root 6 -root 7

here, root 6 -root 7/ (root 6) sq. - (root 7) sq.

It form the identity of(a+b)sq. (a-b) sq.= a sq.- b sq.

root 6- root 7 / 6-7

root 6 -root 7/ -1

I think so the answer