Question

Rationalize the denominator of the following:2/√3-√5​

Answer 1

Answer:

Step-by-step explanation:

a² - b² = (a - b)(a + b)

2(√3 + √5) / (√3 - √5)(√3 + √5) =

(2√3 + 2√5) / [(√3)² - (√5)²] =

(2√3 + 2√5) / (3 - 5) =

- (2√3 + 2√5) / 2

Answer 2

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Answer:

$-\sqrt{3} -\sqrt{5}$   is answer

Step-by-step explanation:

 $\frac{2}{\sqrt{3}-\sqrt{5} }$

We need to rationalize the denominator.

So rationalizing factor of √3-√5 is √3 + √5.

$=>\frac{2}{\sqrt{3}-\sqrt{5} } *\frac{\sqrt{3}+\sqrt{5}}{\sqrt{3}+\sqrt{5}} \\\\=>\frac{2\sqrt{3}+2\sqrt{5} }{3-5}\\\\ =>\frac{2(\sqrt{3}+\sqrt{5})}{-2}\\\\ =>-\sqrt{3} -\sqrt{5}$

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