rationalize the denominator of the following √6 /√3-√2
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Answer:
3√2 + 2√3
Solution:
Here,
We need to rationalize the denominator of
√6/(√3 - √2) .
Thus,
√6/(√3 - √2)
= √6(√3 + √2) / (√3 - √2)(√3 + √2)
= √6(√3 + √2) / [ (√3)² - (√2)² ]
=> √6(√3 + √2) / (3 - 2)
=> √6(√3 + √2)
=> √6•√3 + √6•√2
=> 3√2 + 2√3
Hence,
The required answer is ; 3√2 + 2√3
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