Question

rationalize the denominator of the following route 6/root 3 - root 2

Answer 1

this is the correct answer
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Answer 2

$\textbf{Solution:}$


$\frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} } \\ \\ \frac{ \sqrt{6} }{ \sqrt{3} - \sqrt{2} } \times \frac{ \sqrt{3} + \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \\ \\ \frac{ \sqrt{6}( \sqrt{3} + \sqrt{2} ) }{( \sqrt{3} ) {}^{2} - ( \sqrt{2} ) {}^{2} } \\ \\ \frac{ \sqrt{18} + \sqrt{12} }{3 - 2} \\ \\ \sqrt{18} + \sqrt{12} \\ \\ = > 3 \sqrt{2} + 2 \sqrt{3}$
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