Math, asked by kkk9149, 3 months ago

rationalize the denominator root 5 minus root 3 upon root 5 + root 3​

Answers

Answered by Anonymous
8

Answer:

Rationalize the denominator of:-

 =  \frac{ \sqrt{5} -  \sqrt{3}  }{ \sqrt{5} +  \sqrt{3}  }

Solution:-

 =  \frac{ \sqrt{5} -  \sqrt{3}  }{ \sqrt{5} +  \sqrt{3}  }  \times   \frac{ \sqrt{5} -  \sqrt{3}  }{ \sqrt{5} -  \sqrt{3}  }

 =  \frac{ (\sqrt{5} -  \sqrt{3})^{2}   }{ { (\sqrt{5)} }^{2} -  (\sqrt{ {3)}^{2} }  }

 =  \frac{ { (\sqrt{5)} }^{2} - 2 \times  \sqrt{5}  \times  \sqrt{3} +  (\sqrt{ {3)}^{2} }   }{5 - 3}

  = \frac{5 + 3 - 2 \sqrt{15} }{2}

 =  \frac{ 8 - 2 \sqrt{15} }{2}

 = 4 - 2 \sqrt{15}

Step-by-step explanation:

Hope this helps you.

# By Sparkly Princess

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