Math, asked by 1091998rahultyagi, 9 months ago

Rationalize the denominator root 5 + root 3 e upon root 5 minus root 3

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Answered by aradhanagoswami35122
1

Answer:

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Answered by ankushsaini23
0

Answer:

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According to question:

 Rationalize \: the \: denominator \: of:-

 \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5} -  \sqrt{3}  }

 \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5} -  \sqrt{3}  }  \times  \frac{ \sqrt{5} +  \sqrt{3}  }{ \sqrt{5} +  \sqrt{3}  }

 =  \frac{( { \sqrt{5} +  \sqrt{3}  })^{2} }{( { \sqrt{5} })^{2} - ( { \sqrt{3} })^{2}  }

 =  \frac{( { \sqrt{5} })^{2} + ( { \sqrt{3} })^{2}  + 2( \sqrt{5})( \sqrt{3})   }{5 - 3}

 =  \frac{5 + 3 +  \sqrt[2]{15} }{2}

 =  \frac{8 +  \sqrt[2]{15} }{2}

 =  \frac{2(4 +  \sqrt{15}) }{2}

Cancelling 2 with 2:-

 = 4 +  \sqrt{15}  \: </em><em>Answer:</em><em>-</em><em>

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