Question

rationalize the denominator
$\sqrt{3 } - \sqrt{2 } \div \sqrt{3 + \sqrt{2}$
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Answer 1

Answer:

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Answer 2

$\huge \red{hello} \\ \huge \green{answer}$

$\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} }$

$\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

$\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times 1$

$( \sqrt{3} - \sqrt{2} )( \sqrt{3} - \sqrt{2} )$

$( \sqrt{3} - \sqrt{2} ) ^{2}$

$3 - 2 \sqrt{6} + 2 \\ 5 - 2 \sqrt{6}$

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