Math, asked by kartikgehlot1911, 6 hours ago

rationalize the denominators 1/(2+under root 3)​

Attachments:

Answers

Answered by yashikasingh976159
1

Answer:

1 ×2-root 3

_____________

2+root3 ×2-root3

2-root3

______

4-3

2-root 3 is the Answer

Answered by MagicalCandy
401

Answer⤵️

Given:

  \huge\frac{1}{2 +  \sqrt{3} }

On rationalisation,

 = \frac{1}{2 +  \sqrt{3} }  =  \frac{2 -  \sqrt{3} }{2 -  \sqrt{3} }

  = \frac{2 -  \sqrt{3} }{ {(2)}^{2}  -  \sqrt{ {3}^{2} } }

  = \frac{2 -  \sqrt{3} }{4 - 3}

 =  \frac{2 -  \sqrt{3} }{1}

 = 2 -  \sqrt{3}

Hope this helps!

Similar questions