Math, asked by hsrakshithaiyengar, 10 months ago

Rationalize the denominators.​

Attachments:

Answers

Answered by janardhan9098
1

Step-by-step explanation:

hoping it will help you

Attachments:
Answered by nikshay456
1

Answer:

Hope my answer helps you mate:-)

Step-by-step explanation:

  1.  \frac{1}{ \sqrt{m} }  \times  \frac{ \sqrt{m} }{ \sqrt{m } }  \\  \frac{ \sqrt{m} }{m}
  2.  \frac{1}{ \sqrt{5}  -  \sqrt{3}  }  \times  \frac{  \sqrt{5} +  \sqrt{3}  }{ \sqrt{5} +  \sqrt{3}  }  \\  \frac{ \sqrt{5} +  \sqrt{3}  }{5 - 3 }  \\  \frac{ \sqrt{5} +  \sqrt{3}  }{2}
  3.  \frac{2}{ \sqrt{7}  -  \sqrt{3} }  \times  \frac{ \sqrt{7} +  \sqrt{3}  }{ \sqrt{7 } +  \sqrt{3}  }  \\  \frac{2 \times  \sqrt{7}  +  \sqrt{3} }{ 7 - 3}  \\  \frac{ \sqrt{7} +  \sqrt{3}  }{2}

Similiarly 4 and 5

 \frac{1}{2 +  \sqrt{3} }  \times  \frac{2 -  \sqrt{3} }{2 -  \sqrt{3} } \\  \frac{2 -  \sqrt{3} }{2 - 3}  \\  \sqrt{3}  - 2

If you have time please thank my 10 or 20 answer of maths.

Mark as brainliest answer and follow me ☑️

Similar questions