Question

rationalize the denominators of 3-√5/3+√5​

Answer 1

SOLUTION

$\dfrac{3-\sqrt{5}}{3+\sqrt{5}}$

$\dfrac{3-\sqrt{5}}{3+\sqrt{5}}\times\dfrac{3-\sqrt{5}}{3-\sqrt{5}}$

$\dfrac{(3-\sqrt{5})^2}{3^2-(\sqrt{5})^2}$

$\dfrac{9 \: +\: 5 \: - \:6\sqrt{5}}{9\: - \: 5}$

$\dfrac{14\: - \:6\sqrt{5}}{4}$

$\dfrac{7\:-\:3\sqrt{5}}{2}$

Answer 2

Answer:

3+(2/3)√5

Step-by-step explanation:

applying BODMAS rule

3- √5/3+√5 taking LCM=3 of denominator

= (9 - √5 +3√5) /3

= (9+2√5) / 3

= 3 + (2/3)√5

Answer