Math, asked by parmjitsingh2496, 10 months ago

rationalize the denominators of 7+6√5/7-6√5​

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Answered by mohitgurjar59
6

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Answered by ishwarsinghdhaliwal
4

 \frac{7 + 6 \sqrt{5} }{7 - 6 \sqrt{5} }  \times  \frac{7 + 6 \sqrt{5}}{7 + 6 \sqrt{5}}  \\ =  \frac{(7 + 6 \sqrt{5}) ^{2} }{(7) ^{2} - (6 \sqrt{5})  ^{2}  }  \\   =  \frac{ ({7})^{2}  + (6 \sqrt {5} ) ^{2} + 2(7)(6 \sqrt{5})   }{49 - 180}  \\  =  \frac{49 + 180 + 84 \sqrt{5} }{ - 131}  \\  =  \frac{229 + 84 \sqrt{5} }{ - 131}  \\  =  \frac{ - 229 - 84 \sqrt{5} }{131}

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