Question

Rationalize the denominators of followings
a.) 1 upon √5+√2

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Answer 1

Answer:

Step-by-step explanation:

$\frac{1}{\sqrt{5} +\sqrt2} } =\frac{1}{\sqrt{5} +\sqrt2} }*\frac{\sqrt{5}-\sqrt{2} }{\sqrt{5} -\sqrt2} }\\\frac{1}{\sqrt{5} +\sqrt2} }= \frac{\sqrt{5}-\sqrt{2} }{3}$

Answer 2

Answer:

$\frac{\sqrt{5}-\sqrt{2} }{ 3} }$

Step-by-step explanation:

$\frac{1}{\sqrt{5}+\sqrt{2} }$

$\frac{1}{\sqrt{5}+\sqrt{2} } X \frac{\sqrt{5}-\sqrt{2} }{\sqrt{5} -\sqrt{2} }$

= $\frac{\sqrt{5}-\sqrt{2} }{\sqrt{[5]^{2} - \sqrt{[2]}^{2} } }$

=$\frac{\sqrt{5}-\sqrt{2} }{5-2 } }$

= $\frac{\sqrt{5}-\sqrt{2} }{ 3} }$

it cannot be solved more than this.. as its denominator is not a rational no . , it has been rationalized .

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