Math, asked by Msuri6423, 11 months ago

rationalize the dinominator 8/ root 11- root 7

Answers

Answered by MightyTheLegend
0

Answer:

8\sqrt{11} -8\sqrt{7} /4

Step-by-step explanation:

8/\sqrt{11} -\sqrt{7} \\=8*\sqrt{11} +\sqrt{7}/\sqrt{11} -\sqrt{7}*\sqrt{11} +\sqrt{7}\\=8\sqrt{11} +8\sqrt{7}/(\sqrt{11})^2-(\sqrt{7})^2\\=8\sqrt{11}+8\sqrt{7}/11-7\\=8\sqrt{11} +8\sqrt{7}/4

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