Rationalize the dinominator of 1/root5+root7
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1/√5+√7
=√5-√7×√5-√7
=√5-√7/5-7
=√5-√7/-2
=-(-√5+√7)/-2
=√7-√5/2
Answered by
1
Step-by-step explanation:
root7-root5/2 is the correct answer
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