Question

rationalize the dinominator of 2/√3-√5​

Answer 1

Answer: -(root3+root5)

Step-by-step explanation:

2/(root3-root5)

2(root5+root3)/(3-5)

2(root5+root3)/(-2)

-(root3+root5)

Answer 2

Answer:

$\Large\sf\underline\red{answer:-}\ \\ \\ \sf\blue{ - \sqrt{3} - \sqrt{5} } \\ \\ \\ \Large\sf\underline\red{solution:-} \\ \\\sf \frac{2}{ \sqrt{3} - \sqrt{5} } \\ \\ → \: \: \: \sf\frac{2}{ \sqrt{3} - \sqrt{5} } \times \frac{ \sqrt{3} + \sqrt{5} }{ \sqrt{3} + \sqrt{5} } \\ \\ → \: \: \: \: \:\sf \frac{2 \sqrt{3} + 2 \sqrt{5} }{3 - 5} \\ \\ → \: \: \: \sf \frac{2( \sqrt{3} + \sqrt{5} ) }{ - 2} \\ \\ → \: \: \: \: \: \: \: \sf \frac{( \sqrt{3 + } \sqrt{5}) }{ - 1} \\ \\ →\sf \: \: \: ( - \sqrt{3} - \sqrt{5} ) \\ \\ \\ \\ \Large\sf\underline\red{hence \: verified}$