rationalize the dinominator of 7+3√5/7-3√5
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Answer:
7+3
5
)/(7–3
5
)
Let us rationalize the denominator, we get
(7+3
5
)/(7–3
5
)=[(7+3
5
)(7+3
5
)]/[(7–3
5
)(7+3
5
)]
=[(7+3
5
)2]/[72–(3
5
)2]
=[72+(3
5
)2+2.7.3
5
]/[49–9.5]
=[49+9.5+42
5
]/[49–45]
=[49+45+42
5
]/[4]
=[94+42
5
]/4
=2[47+21
5
]/4
=[47+21
√5
]/2
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