rationalize the dinominator of 7+3√5/7-3√5
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Answered by
1
Answer:
(7+35)/(7–35)
Let us rationalize the denominator, we get
(7+35)/(7–35)=[(7+35)(7+35)]/[(7–35)(7+35)]
=[(7+35)2]/[72–(35)2]
=[72+(35)2+2.7.35]/[49–9.5]
=[49+9.5+425]/[49–45]
=[49+45+425]/[4]
=[94+425]/4
=2[47+215]/4
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=[47+215]/2
Answered by
1
Answer:
step by step
7+3√5/7-3√5 ×7+3√5/7+3√5
=(7+3√5)^2/7^2-3√5^2
=49+42√5+45/49-45
=94+42^5/4
=47+21√5/2
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