Question

rationalize the dinominatorof root 3 by2-3root 5​

Answer 1

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Q:-rationalize the dinominatorof root 3 by2-3root 5

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$⟹</p><p> \frac{ \sqrt{3} }{2 - 3 \sqrt{5} }$

$⟹</p><p> \frac{ \sqrt{3} }{2 - 3 \sqrt{5} } \times \frac{2 + 3 \sqrt{5} }{2 + 3 \sqrt{5} }$

$⟹</p><p> \frac{ \sqrt{3}(2 + 3 \sqrt{5} )}{ {(2)}^{2} - {(3 \sqrt{5}) }^{2} }$

$⟹</p><p> \frac{2 \sqrt{3} + 3 \sqrt{3} \sqrt{5} }{4 - 45}$

$⟹</p><p> \frac{2 \sqrt{3} + 3 \sqrt{3} \sqrt{5} }{ - 41}$

$⟹</p><p> \frac{ - (2 \sqrt{3} - 3 \sqrt{3} \sqrt{5}) }{41}$

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Answer 2

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