Question

rationalize the dominator of cube root of five and root of six​

Answer 1

Answer

$\frac{ \sqrt[3]{5} }{ \sqrt{6} } = \frac{ {5}^{ \frac{1}{3} } }{ \sqrt{6} } \times \frac{ \sqrt{6} }{ \sqrt{6} } \\ \\ = > \frac{ {5}^{ \frac{1}{3} } \times {6}^{ \frac{1}{2} } }{6}$