Question

Rationalize the factor of 2√3-2​

Answer 1

Answer:

We know that rationalising factor of a irritional number is the number when we multiply by the given irrational number then it gives a rational number.

so here we have a irrational number

2√3-2 so it's rationalising factor can be variable

Let's find it :-

2√3-2 × ( 2√3)

2√3 × 2√3 - 2

4 × 3 - 2

12 - 2

10 which is a rational number

So the rationalising factor of 2√3-2 is 2√3

Now,

(2√-2)/2√3

{2√3 - 2(2√3)}/ 2√3 × 2√3

(2√3 × 2√3-2 × 2√3) / (2√3)²

12 - 4√3/12

4(3 - √3)/12

3-√3 Ans....

Answer 2

Answer:

1/

$1 \div 2 \sqrt{3} - 2 \times 2 \sqrt{3} + 2 \div 2 \sqrt{3} + 2 \\ 2 \sqrt{3} + 2 \div (2 \sqrt{3})^{2} - (2)^{2} \\ 2 \sqrt{3} + 2 \div 12 - 4 \\ 2 \sqrt{3} + 2 \div 8 \\ 2( \sqrt{3} + 1) \div 8 \\ \sqrt{3} + 1 \div 4(ans)$

I thik it will help u