Math, asked by shirin14693gmailcom, 1 year ago

rationalize the factor of 2 + root 3 upon 2 minus root 3 + 2 minus root 3 upon 2 + root 3​

Answers

Answered by Darsh05
1

Answer:

14

Step-by-step explanation:

 \frac{2 +  \sqrt{3} }{2 -  \sqrt{3} }  +  \frac{2 -  \sqrt{3} }{2 +  \sqrt{3} }  \\  \\  =   \frac{(2 +  \sqrt{3} )^{2} }{(2 -  \sqrt{3})(2 +  \sqrt{3} ) } +  \frac{ {(2 -  \sqrt{3}) }^{2} }{(2 +  \sqrt{3})(2 -  \sqrt{3} ) }  \\  \\  =   \frac{ {2}^{2}  +  { (\sqrt{3}) }^{2}  + 2 \times 2 \sqrt{3} }{ {2}^{2}  -   {( \sqrt{3} )}^{2}  }  +  \frac{ {2}^{2}  +  {( \sqrt{3}) }^{2} - 2 \times 2 \sqrt{3}  }{ {2}^{2}  -    { (\sqrt{3}) }^{2}   }  \\  \\  =  \frac{4 + 3 + 4 \sqrt{3} }{4 - 3}  +  \frac{4 + 3 - 4 \sqrt{3} }{4 - 3}  \\  \\  = 7 + 4 \sqrt{3}  + 7 - 4 \sqrt{3}  \\  = 14

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