Question

rationalize the following:1/√2+√5​

Answer 1

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$= \frac{1}{ \sqrt{2} + \sqrt{5} }$

$= \frac{1}{ \sqrt{2} + \sqrt{5} } \times \frac{\sqrt{2} - \sqrt{5} }{ \sqrt{2} - \sqrt{5} } \\ \\ = \frac{\sqrt{2} - \sqrt{5} }{ (\sqrt{2} - \sqrt{5})(\sqrt{2} + \sqrt{5})}$

using the identity

x²-y²= (x-y) (x+y)

$= \frac{ \sqrt{2} - \sqrt{5} }{2 - 5} \\ \\ = \frac{ \sqrt{2} - \sqrt{5} }{ - 3}$

hope it will help you

Answer 2

Step-by-step explanation:

1/√2+√5*√2-√5/√2-√5

√2-√5/2-5

√2-√5/-3

thank you✔❤