Question

Rationalize the following fraction :
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Answer 1

Answer:

one apon root Three square plus root two square

then, three plus two equal to six

Answer 2

$\frac{1}{ \sqrt{3} + \sqrt{2} } \\ = \frac{1( \sqrt{3} - \sqrt{2} ) }{( \sqrt{3} + \sqrt{2})( \sqrt{3} - \sqrt{2}) } \\ = \frac{ \sqrt{3} - \sqrt{2} }{( \sqrt{3} ) {}^{2} - ( \sqrt{2} ) {}^{2} } \\ = \frac{ \sqrt{3} - \sqrt{2} }{3 - 2} \\ = \frac{ \sqrt{3} - \sqrt{2} }{1} \\ = \sqrt{3} - \sqrt{2}$