rationalize this denominator:1/root5-root 3
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Step-by-step explanation:
1/(√5 - √3)
multiplying numerator and denominator by (√5+√3) [ why?, because denominator is in (a-b) form so we multiply with (a+b) form so as to get (a2-b2) and get rid of roots in denominator. this is called rationalisation)
1*(√5+√3)/!√5-√3)(√5+√3)
= (√5+√3)/(√5)^2 - {√3)^2
= (√5+√3)/(5-3)
= (√5+√3)/2
we may write it as
(1/2)*(√5+√3)
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