Question

Rationalize this denominator 8/7-root3
$3$
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Answer 1

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$\red{\underline{{ \bf Question }}}$

• $\sf Rationalize \: the \: denominator \: \dfrac{8}{7- \sqrt{3}}$

$\red{\underline{{ \bf Solution }}}$

$\sf \implies\dfrac{8}{7 - \sqrt{3} } \times \dfrac{7 + \sqrt{3} }{7 + \sqrt{3} }$

$\sf \implies\dfrac{8(7 + \sqrt{3}) }{ ({7})^{2} - ( \sqrt{3} {)}^{2} }$

$\sf \implies \dfrac{56 + 8 \sqrt{3} }{49 - 3}$

$\sf \implies \dfrac{56 + 8 \sqrt{3} }{47}$

$\sf \implies \dfrac{28 + 8 \sqrt{3} }{23}$

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Answer 2

Answer:

1.518

Step-by-step explanation:

(8/7-√3)×(7+√3/7+√3)

=8(7+√3)/49-3

=8(7+√3)/46

=4(7+√3)/23

=1.518