Question

rationalize this question​

Answer 1

Answer:

$\boxed{\underline{\Huge{\mathtt{13+2\sqrt{42}}}}}$

Step-by-step explanation:

$\dfrac{\sqrt{7}+\sqrt{6}}{\sqrt{7}-\sqrt{6}}\\\\\implies \dfrac{\sqrt{7}+\sqrt{6}}{\sqrt{7}-\sqrt{6}} \times \dfrac{\sqrt{7}+\sqrt{6}}{\sqrt{7}+\sqrt{6}}\\\\\implies \dfrac{\sqrt{7}^2+\sqrt{6}^2+2(\sqrt{7})(\sqrt{6})}{\sqrt7^2-\sqrt6^2}\\\\\implies \dfrac{(\sqrt{7}+\sqrt{6})^2}{7-6} = \dfrac{(\sqrt{7}+\sqrt{6})^2}{1}\\\\\implies \dfrac{13+2\sqrt{42}}{1} = \bold{13+2\sqrt{42}}$

Answer 2

Answer:

13 + 2√42

Step-by-step explanation:

√7 + √6 / √7 - √6

√7  + √6 × √7 + √6 / √7 - √6 × √7 + √6

( √7 + √6 )^2 / ( √7 )^2 - ( √6 )^2

7 + 6 + 2√42 / 7 - 6

13 + 2√42 / 1

= 13 + 2√42

hope it helps

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