Math, asked by elena78, 1 year ago

rationalize this right now​

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Answers

Answered by Anonymous
12

ANSWER IN ATTACHEMENT

Regards

Akshat Rajput

◼ MATHS ARYABHATTA

◼ BRAINLY CHALLENGER

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elena78: because a YouTuber knows how to deal with hate
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Answered by sivaprasath
10

Answer:

Step-by-step explanation:

Given :

To rationalise the denominator of the fraction

\frac{\sqrt{5}+5}{\sqrt{6}+\sqrt{5}}

Solution :

We know that,

The denominator of the fraction are under square roots,

So,

We shall use the algorithm of the identity :

(a + b)(a - b) = a^2 - b^2

Let a = \sqrt{6} & b = \sqrt{5}

So,.

It will become (\sqrt{6}+\sqrt{5})(\sqrt{6}-\sqrt{5}) = (\sqrt{6})^2-(\sqrt{5})^2 = 6 - 5 = 1

So,

By multiplying (\sqrt{6}-\sqrt{5}) on both numerator & denominator,

We get,

\frac{\sqrt{5}+5}{\sqrt{6}+\sqrt{5}} \times \frac{\sqrt{6}-\sqrt{5}}{\sqrt{6}-\sqrt{5}}

\frac{(\sqrt{5}+5)(\sqrt{6}-\sqrt{5})}{(\sqrt{6}+\sqrt{5})(\sqrt{6}-\sqrt{5})}

⇒  \frac{(\sqrt{5}+5)(\sqrt{6}-\sqrt{5})}{1} (rationalised the denominator),.

⇒  \sqrt{30} - 5+5\sqrt{6}-5\sqrt{5}


elena78: where is the answer
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