Rationalize y²÷x+root x²+y²
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Answered by
5
Answer :
Now,
y²/{x + √(x² + y²)}
We rationalise the denominator by multiplying both the numerator and denominator by
{x - √(x² + y²)}.
So,
y²/{x + √(x² + y²)} × [{x - √(x² + y²)}/{x - √(x² + y²)}]
= y²{x - √(x² + y²)} × 1/[{x + √(x² + y²)}{x - √(x² + y²)}]
= y²{x - √(x² + y²)}/[x² - (x² + y²)]
= y²{x - √(x² + y²)}/( - y²)
= - {x - √(x² + y²)}
#MarkAsBrainliest
Now,
y²/{x + √(x² + y²)}
We rationalise the denominator by multiplying both the numerator and denominator by
{x - √(x² + y²)}.
So,
y²/{x + √(x² + y²)} × [{x - √(x² + y²)}/{x - √(x² + y²)}]
= y²{x - √(x² + y²)} × 1/[{x + √(x² + y²)}{x - √(x² + y²)}]
= y²{x - √(x² + y²)}/[x² - (x² + y²)]
= y²{x - √(x² + y²)}/( - y²)
= - {x - √(x² + y²)}
#MarkAsBrainliest
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3
Answer:
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