rationalize4+√5/4-√5+ 4-√5/4+√5
Answers
Answer:
8
Step-by-step explanation:
Rationalize the following:
4 + (sqrt(5))/4 - sqrt(5) + 4 - (sqrt(5))/4 + sqrt(5)
Put each term in 4 + (sqrt(5))/4 - sqrt(5) + 4 - (sqrt(5))/4 + sqrt(5) over the common denominator 4: 4 + (sqrt(5))/4 - sqrt(5) + 4 - (sqrt(5))/4 + sqrt(5) = 16/4 + (sqrt(5))/4 + (-4 sqrt(5))/4 + 16/4 + (-sqrt(5))/4 + (4 sqrt(5))/4:
16/4 + (sqrt(5))/4 + (-4 sqrt(5))/4 + 16/4 + (-sqrt(5))/4 + (4 sqrt(5))/4
16/4 + (sqrt(5))/4 - (4 sqrt(5))/4 + 16/4 - (sqrt(5))/4 + (4 sqrt(5))/4 = (16 + sqrt(5) - 4 sqrt(5) + 16 - sqrt(5) + 4 sqrt(5))/4:
(16 + sqrt(5) - 4 sqrt(5) + 16 - sqrt(5) + 4 sqrt(5))/4
16 + sqrt(5) - 4 sqrt(5) + 16 - sqrt(5) + 4 sqrt(5) = 32:
32/4
The gcd of 32 and 4 is 4, so 32/4 = (4×8)/(4×1) = 4/4×8 = 8:
Answer:
8
Here u go
Hope it helps u