Question

Rationalizing factor for the denominator of the
expression1/root7-3
is
O A. root7 - 3
O B. 7-√3
O c. root7+3
O D. root7+ √3​

Answer 1

Answer:

answer will be c part i.e.√7+3

Answer 2

Step-by-step explanation:

$\frac{1}{ \sqrt{7} - 3} \times \frac{ \sqrt{7} + 3}{ \sqrt{7} + 3 } \\ \: \: \: \: \: we \: \: will \: \: use \: \: this \: \: identity \\ (x - y)(x + y) = {x}^{2} - {y}^{2} \\ \frac{ \sqrt{7} + 3}{( \sqrt{7} {)}^{2} - (3 {)}^{2} } \\ = \frac{ \sqrt{7} + 3}{7 - 9} \\ = \frac{ \sqrt{7} + 3 }{ - 2} \\ = \frac{ - (\sqrt{7} + 3)}{2} \\ = \frac{ - \sqrt{7} - 3}{2}$

I hope it will help you out