Question

rationalizing the denominator​

Answer 1

Answer:

$\frac{1}{ \sqrt{3} - 1 } \\ = )lets \: rationalize \\ = ) \frac{1}{ \sqrt{3} - 1} \times \frac{ \sqrt{3} + 1}{ \sqrt{3} + 1 } \\ ( a - b)(a + b) = {a}^{2} - {b}^{2} \\ = ) \frac{ \sqrt{3} + 1 }{ {( \sqrt{3} )}^{2} - {(1)}^{2} } \\ = ) \frac{ \sqrt{3} + 1 }{3 - 1 } \\ = ) \frac{ \sqrt{3} + 1}{2}$

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