rationalizing the denominator of 40/root of 40-root of 80.It is being given that √5 = 2.236 and √10 = 3.162
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Hi ,
√5 = 2.236 ,
√10 = 3.162
40/( √40 - √80 )
= 40/ [ ( √2×2×10 ) - ( √4×4×5 ) ]
= 40/[2√10 - 4√5 ]
= 40/ [ 2( √10 - 2√5 ) ]
= 20/[ √10 - 2√5 ]
= [ 20 ( √10 + 2√5 ) ]/[(√10-2√5)(√10+2√5)]
= [20( √10 + 2√5 ]/[ ( √10 )² - ( 2√5 )² ]
= [ 20(√10 + 2√5 ) ]/( 10 - 20 )
= [ 20 ( √10 + 2√5 ) ]/( -10 )
= ( - 2 ) ×( √10 + 2√5 )
= ( -2 )×( 3.162 + 2 × 2.236 )
= ( -2 ) × ( 3.162 + 4.472 )
= ( -2 ) × 7.634
= - 15.268
I hope this helps you.
: )
√5 = 2.236 ,
√10 = 3.162
40/( √40 - √80 )
= 40/ [ ( √2×2×10 ) - ( √4×4×5 ) ]
= 40/[2√10 - 4√5 ]
= 40/ [ 2( √10 - 2√5 ) ]
= 20/[ √10 - 2√5 ]
= [ 20 ( √10 + 2√5 ) ]/[(√10-2√5)(√10+2√5)]
= [20( √10 + 2√5 ]/[ ( √10 )² - ( 2√5 )² ]
= [ 20(√10 + 2√5 ) ]/( 10 - 20 )
= [ 20 ( √10 + 2√5 ) ]/( -10 )
= ( - 2 ) ×( √10 + 2√5 )
= ( -2 )×( 3.162 + 2 × 2.236 )
= ( -2 ) × ( 3.162 + 4.472 )
= ( -2 ) × 7.634
= - 15.268
I hope this helps you.
: )
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