Question

rationalozing factor of ⁴√343

Answer 1

$\sqrt[4]{343} = \sqrt[4]{49 \times 7} \\ = > \sqrt[4]{343} = \sqrt[4]{ {7}^{2} \times 7 } = \sqrt{7} \times \sqrt[4]{7}$
=>√(7√7)
$= {7}^{ \frac{3}{4} }$