Math, asked by sm8319000, 1 month ago

Rationlise the denominator of 1

2−√3​

Answers

Answered by Anonymous
1

1/(2-√3) = 1/(2-√3) ×(2+√3)/(2+√3) = 2+√3/(2^2-√3^2) = 2+√3/4-3 = (2+√3)/1 = 2+√3

hope it helps you...be happy

Answered by Anonymous
2

Answer:

 \frac{2 +  \sqrt{3} }{1}

Step-by-step explanation:

Solution -

➠‎ ‎Let's rationalise the given irrational number.

 \frac{1}{2 -  \sqrt{3} }  \\  \\  =   \frac{1}{2 -  \sqrt{3} }  \times  \frac{2 +  \sqrt{3} }{2 +  \sqrt{3} }  \\  \\   (a - b {)}^{2}   = (a + b)(a - b) \\  \\ (2 -   \sqrt{3} )(2 +  \sqrt{3} ) =  (2  -  \sqrt{3}  {)}^{2}  \\  \\  =  {(2)}^{2}  - ( \sqrt{3}  {)}^{2}  \\  \\  = 4 - 3 \\  \\  = 1 \\  \\  =  \frac{2 +  \sqrt{3} }{1}

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