Question

rationlise the denominator of the following real Numbers:1/3+√5​

Answer 1

Answer:

$\dfrac{1}{3+\sqrt{5} }$

Multiplying both numerator and denominator by conjugate

$\dfrac{1}{3+\sqrt{5} }\times\dfrac{3-\sqrt{5}}{3-\sqrt{5} }$

$\dfrac{3-\sqrt{5}}{3^2-(\sqrt{5})^2 }$

$\dfrac{3-\sqrt{5}}{9-5 }$

$\dfrac{3-\sqrt{5}}{4 }$