rationlisze the denominator 1/√3-√2
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the answer turns out to be √3+√2
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multiply both numerator &denominator by its conjugates
1*root3+root2/root3 -root2*root3+root2
=root3+root2/root3^2-root2^2
=root3 +root2/3-2
=root3+root2
1*root3+root2/root3 -root2*root3+root2
=root3+root2/root3^2-root2^2
=root3 +root2/3-2
=root3+root2
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