Question

Ratonalise the denominater of root3minus root 2 by root 3plus root 2

Answer 1

Hii dear here is your answer...


This answer is verified ✅✅✅

$\frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} + \sqrt{2} } \times \frac{ \sqrt{3} - \sqrt{2} }{ \sqrt{3} - \sqrt{2} }$

$\frac{ ({ \sqrt{3 } - \sqrt{2} )}^{2} }{ { (\sqrt{3}) }^{2} - {( \sqrt{2} )}^{2} }$

$\frac{ {( \sqrt{3}) }^{2} + { (\sqrt{2}) }^{2} - 2 \times \sqrt{3} \times \sqrt{2} }{3 - 2}$

$\frac{3 + 2 - 2 \sqrt{6} }{1}$

$5 - 2 \sqrt{6}$

Hope it will help you....