Question

Raveena is 7 years older than her sister Praveena. The sum of their ages six years later
will be 35. Find their present ages.
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Answer 1

Answer:

Raveena is 7 years older than Praveena. Therefore, the age of Raveena would be (x + 7).After 6 years, age of praveena will be x+6 and raveena will be x+7+6 i.e. x+13 and they given condition that sum of ages of both after six years will be 35 So,we can write x+6+x+13=35 .Hence solve the linear equation and calculate value for x.

Complete step-by-step answer:

As mentioned in the hint, Praveena’s age is ‘x’ and the age of Raveena is (x + 7).

Present age of Praveena = x

Present age of Raveena = (x + 7)

So, age of Praveena after 6 years = (x + 6)

And, age of Raveena after 6 years = (x + 7 + 6) = (x + 13)

As mentioned in the question, the sum of the ages of Raveena and Praveena after 6 years will be 35.

Therefore, (x + 13) + (x + 6) = 35

2x + 19 = 35

2x = 35 – 19

x = 162

= 8

So, as the value of ‘x’ is 8, therefore, Praveena’s age is 8 and the age of Raveena is (x + 7) = (8 + 7) = 15

Age of Praveena = 8

Age of Raveena = (8 + 7) = 15

Hence, the answer of the question is (c) Raveena = 15 years, Praveena = 8 years

Step-by-step explanation:

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