Question

Ravi and Ajay start simultaneously from a place A towards B 60 km apart. Ravi's speed is 4km/h less than that of Ajay. Ajay, after reaching B, turns back and meets Ravi at a places 12 km away from B. Ravi's speed is:
A.12 km/h
B.10 km/h
C.8 km/h
D.6 km/h

Answer 1

ĀNSWĒR ⏬⏬

C.8 km/h



✔Ajay → (x+4) kmph.
A to B 60 km

Ravi → x kmph.

Let the speed of Ravi be x kmph;

Hence Ajay's speed = (x+4) kmph;

Distance covered by Ajay = 60 + 12 = 72 km;

Distance covered by Ravi = 60 - 12 = 48 km.

According to question,

72/(x+4) = 48/x

Or, 3/(x+4) = 2/x

3x = 2x+8

Or, x = 8 kmph.


Thanks ✌✌✌✌

Answer 2

C . 8 km/ h it's a good and right answer