Ravi and Anshul are pushing a wooden box from the same side in such a way that the force applied by Anshul is twice that applied by Ravi. The frictional force acting between the surface of the box and the ground is one-tenth of the total force applied by Ravi and Anshul. As a result, the box experiences a net unbalanced force of 27 N.
What is the force applied by Anshul?
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Answer:
20 N
Explanation:
since both rare in same direction forces will be added .friction force is in other direction so it will be subtracted
x+2x-1=10x3x=27
3x+3x+10=27
30x-3x=270
27x=270
x=10
therefore force by samarth =2xx
20N
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