Math, asked by mumbose6054, 10 months ago

Ravi buys two table for at Rs 1485 each he incures a loss of10percent on one and a profit of 10 percent on the other by selling them Find his profit or loss​

Answers

Answered by chhavishkaushik
0

susant bhai ki yaad aa rahi ha kiya aap uneh bola sakete hai please,

Answered by sparsh1923
0

Given, the selling price = 1485

Let the cost of one table sold by shopkeeper which gains 10% be x. gain=(10/100)x=0.1x

So since selling price= x+0.1x=1.1x=1485=> x=14850/11=1350

Profit=1485-1350= ₹135 .

let the cost of one table which loss 10% be y. Loss=10/100(y) =0.1y.

So selling price of the table =y-0.1y=0.9y=1485=> y=14850/9= ₹1650

Loss=1650- 1485= ₹165 .

Net loss=165-135= ₹30.

Cost of two tables=1650+1350=₹3000.

Loss%=30(100)/3000=1 % .

Hence there is a loss of 1% .

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