Ravi buys two table for at Rs 1485 each he incures a loss of10percent on one and a profit of 10 percent on the other by selling them Find his profit or loss
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susant bhai ki yaad aa rahi ha kiya aap uneh bola sakete hai please,
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Given, the selling price = 1485
Let the cost of one table sold by shopkeeper which gains 10% be x. gain=(10/100)x=0.1x
So since selling price= x+0.1x=1.1x=1485=> x=14850/11=1350
Profit=1485-1350= ₹135 .
let the cost of one table which loss 10% be y. Loss=10/100(y) =0.1y.
So selling price of the table =y-0.1y=0.9y=1485=> y=14850/9= ₹1650
Loss=1650- 1485= ₹165 .
Net loss=165-135= ₹30.
Cost of two tables=1650+1350=₹3000.
Loss%=30(100)/3000=1 % .
Hence there is a loss of 1% .
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