Math, asked by Mohanish98, 8 months ago


Ravi can pack 54 pens or 72 pencils by working 6 hours a day and Sunil can pack 45 pens or 70 pencils by working 5 hours a day. They received an order of packing 4500 pens and 5600
pencils. If they work together for 10 hours a day then in how many minimum days can they deliver the order?
Pick ONE option
A) 60 days
B) 50 days
C) 55 days
D) 45 days​

Answers

Answered by amitnrw
3

Given :  Ravi can pack 54 pens or 72 pencils by working 6 hours a day and Sunil can pack 45 pens or 70 pencils by working 5 hours a day. They received an order of packing 4500 pens and 5600  pencils

To find : working together for 10 hours a day then in how many minimum days can they deliver the order

Solution:

Ravi can pack 54 pens or 72 pencils by working 6 hours a day

=> Ravi can pack 9 pens or 12 pencils by working 1 hours a day

=> Ravi can pack 90 pens or 120 pencils by working 10 hours a day

Sunil can pack 45 pens or 70 pencils by working 5 hours a day.

=> Sunil can pack 9 pens or 14 pencils by working 1 hours a day.

=> Sunil can pack 90 pens or 140 pencils by working 10 hours a day.

Ravi & Sunil both can pack 90 pens in a day

but sunil can pack 140 pencils in day

Let sunil pack all the  5600 pencils  = 5600/140  = 40 Days

Now 4500 pens can be packed in 4500/90  = 50 Days

45 Days by Ravi  & 5 Days by Sunil

Sunil Total days = 40 + 5  = 45  Days

Hence They can deliver the project in  45 Days  

Option C is correct

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