Question

Ravi goes to the supermarket and buys chocolates, chips and pastries in the ratio of 7:13:19 respectively. The cost of chips, pastries and chocolates in the ratio 7:11:23 respectively. What percentage of the expenses in the supermarket was from chocolates? a)0.28 b)0.32 c)0.35 d)Cannot be determined​

Answer 1

Answer:

hope this is help full

Step-by-step explanation:

Let Ram buy 7x, 13x, 19x chocolates, chips and pastries respectively.

Let the cost of the chocolates, chips and pastries be 23y, 7y, 11y respectively.

Total expenses = xy (23 x 7 + 7 x 13 + 11 x 19) percentage expenses from chocolates = 100 x (23y x 7x)/ (xy (23 x 7 + 7 x 13 + 11 x 19))

= 161 x 100/(161 + 91 + 209)

= 161 x 100/461 ~= 35%.

Answer 2

Answer:

Required percentage is 41.81%.

Step-by-step explanation:

Given, Ravi buys chocolates, chips and pastries.And ratio of chocolates , chips and pastries is 7:13:19.

Let number of chocolates be 7x.

Let number of chips be 13x and number of pastries be 19x.

Again given that the cost of chips, pastries and chocolates in the ratio 7:11:23.

Let cost of chips be 7y rupees and cost of pastries be 11y rupees and cost of chocolates be 23y rupees.

Now,

Total cost of chocolates $= (7x \times 23y) = 161xy \: rupees$

and total cost of chips $= (13x \times 7y) = 91xy \: rupees$

and total cost of pastries $= (19x \times 7y) = 133xy \: rupees$

So,his total expenses

$= 161xy + 91xy + 133xy \\ = 385xy \: rupees$

Here 385xy means 100%

So, 161xy means $\frac{100 \times 161xy}{385xy}%$ =41.81%

This is a problem of percentage.

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