Question

Ravi has a bag full of 10 nestle and 5 cadbury chocolates. out of these, he draws two chocolates. what is the probability that he would get at least one nestle chocolate?

Answer 1

Solution: The total number of ways in which two chocolates can be drawn is

n(S) = 15C2 = 105

The number of ways in which at least one is nestle is:

n(E) = 10C1 * 5C1 + 10C2 * 5C0

      =10 * 5 + 45 * 1

      = 50 + 45

      = 95

Therefore the probability of at least one nestle is $\frac{95}{105} =\frac{19}{21}$

Answer 2

Answer:

19/105

Step-by-step explanation:

"guys very simple"

total no of chocolate=15

drawn=2 so 15c2

at least 1 (minimum 1 ,maximum 2)

minimum =10c1

max=10c2

so, min=10c1*5c1

max=10c2

min + max =(10c1*5c1+10c2)/15c2=19/21